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Rd sharma solutions

A man goes 15 m due west and then 8 m due north. How far is he from the starting point?

Given a man goes 15 m due west and then 8 m due north

Let O be the starting point and P be the final point.

Then OP becomes the hypotenuse in the triangle.

So by using the Pythagoras theorem, we can find the distance OP.

OP^2 = 15^2 + 8^2

OP^2 = 225 + 64

OP^2 = 289

OP = 17

Hence, the required distance is 17 m.

A man goes 15 m due west and then 8 m due north. How far is he from the starting point?

Given a man goes 15 m due west and then 8 m due north

Let O be the starting point and P be the final point.

Then OP becomes the hypotenuse in the triangle.

So by using the Pythagoras theorem, we can find the distance OP.

OP^2 = 15^2 + 8^2

OP^2 = 225 + 64

OP^2 = 289

OP = 17

Hence, the required distance is 17 m.

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